Question

Question No. 4
Lowest freezing point among the following aq. solution is shown by
O 0.2 m Glucose
O 0.15 m NaCl
0.1 m CaCl2
0.1 m K4[Fe(CN)6]​

Answer 1

Answer:

0.1 m CaCl2 you have to remember

Answer 2

Explanation:

where Tf is the change in freezing point, i is Vant Hoff factor, m is molality and k is freezing point constant.

Also, 1% NaCl will have Van't Hoff factor 2 and 1 % CaCl2 will have Vant Hoff factor i as 3.

Thus 1% CaCl2 produces most ions and thus lowers the freezing point to the maximum value.