Question

Question no. 40 please

Answer 1

$x = a {b}^{2} {c}^{3} ...... { z}^{26} \\ y = {a}^{26} {b}^{25} {c}^{24} .......z \\ abcd... z = \sqrt[54]{64} \\ xy = {(abcd.....z)}^{27} \\ xy = {( \sqrt[54]{64} ) }^{27} = \sqrt{64} = 8$
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