Question

Question no 41 find the perimeter of a rectangle whose length is 40 m diagonal is 41 m

Answer 1

Answer:

98m

Step-by-step explanation:

use Pythagoras theorem .

breadth=√(daigonal^2 -length^2)

breadth=√(41^2-40^2)

breadth=9m.

so perimeter of rectangle=2(L+B)

=2(40+9)

=98m

Answer 2

perimeter of rectangle=2(l+b)

=2(40+9)

=2×49

=98

half answer in the photo