Question

Question No. 41 to 45 are based on the given text. Read the text carefully and answer the
questions:
In a forest, a big tree got broken due to heavy rain and wind. Due to this rain the big
branches AB and AC with lengths 5m fell down on the ground. Branch AC makes an angle
of 30° with the main tree AP. The distance of Point B from P
is 4 m. You can observe that AABP is congruent to ACP.
41. AACP and AABP are congruent by which criteria?
5 W
P190
a) SAS
b) ASA
c) RHS
d) SSS
42. What is the length of CP?
a) 3 m
b) 4 m
c) 10 m
d) 5 m
43. What is the value of ZBAP?
a) 40°
b) 30°
c), 50°
60°
44. What is the value of LAPB?
a) 40°
b) 50°
c) 60°
) 90°
45. What is the height of the remaining tree?
a) 3 m
b) 5 m
c) 4 m
g) 10 m
swer the​

Answer 1

Answer:

41. c)RHS

42. b) 4m

43. d)60°

44.d)90°

45.a)3m

Step-by-step explanation:

41. In the triangle ACP and ABP

AC=AB(given as 5m)

AP=AP(common side)

angle APC=angle APB (90°)

This both the triangles are congruent by RHS Congruency criteria

42. by CPCT we can say that CP=BP=4m

43.angle ABP+ angle BPA + angle PAB = 180° (angle sum property of triangles )

we know ABP=30°

BPA=90°

30°+90°+PAB=180°

PAB=180°-120°

PAB=60°

44. APB= 90° as the tree is perpendicularly attached to the ground.

45. by Pythagoras theorem we can say that

AP²+PB²=AB²

AP²=AB²-PB²

AP²=5²-4²

AP²=25-16

AP²=9

AP²=√9

AP=3

Therefore the remaining length of the tree is 3m.