Question No. 45
Behind a thin converging lens having both the surface of the same radius 10cm, a plane miror has been placed. The image of an object at a
distance 40 cm from the lens is formed at same position. What is the refractive index of lens?
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Hence the refractive index of the lens is μ = 9 / 8
Explanation:
- Radius of lens = 10 cm
- Distance of object = 40 cm
- To Find: Refractive index of the kens "n" = ?
Solution:
Using lens mirror formula;
1/ f = ( μ−1 ) ( 1/ R1 - 1/ R2 )
=> 1/ 40 = ( μ−1 ) ( 1/ 10 + 1/ 10)
1 / 40 = ( μ−1 ) 2 / 10
1 = ( μ−1 ) 2 / 10 x 40
1 = ( μ−1 ) 2 x 4
1 = ( μ−1 ) 8
1 = 8 μ - 8
μ = 9 / 8
Hence the refractive index of the lens is μ = 9 / 8
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