Math, asked by panku98, 1 year ago

question no. 5 can you explain it​

Attachments:

Answers

Answered by prabhas4841
1

Answer:



Let S ={HHH,HHT,HTH,THH,HTT.THT,TTH,TTT}

Consider event A where only heads comes

A= {HHH,}

Consider event B where only tail comes

B= {TTT}

A and B are mutually exclusive since no element match.

Next Consider event A where two heads come

A = {HHH,HHT,HTH,THH,}

Event B where atleast two tail come

B ={HTT.THT,TTH,TTT}

Consider event C where only 3 tail comes

C={TTT}

A B and C are three mutually exclusive  event ( since none of the set element intersect)

also

A union B union C = {HHH,HHT,HTH,THH,HTT.THT,TTH,TTT} = S

hence A B and C are 3 exhaustive sets.

Similar questions