Question

Question No.5
In Dumas method for estimation of nitrogen 0.30 g
of an organic compound gave 50 ml of nitrogen
collected at 300 K and 715 mm of Hg pressure.
The percentage composition of nitrogen in the
compound is, if aqueous tension at 300 K is 15 mm
of Hg.​

Answer 1

Answer:

6.25 %

Explanation:

Here,

Mass of organic substance =0.3 g

Volume of Nitrogen collected =50 mL

Temperature (T1)=300 K

Vapour pressure of water =15 mm

Actual pressure of dry nitrogen =715−15=700 mm

At STP, we know that P2=760 mm and T2 =273K then V2 =?

====> P1 V1/ T1 = P2V2/ T2

====>( 700 x 50) /309 = (700 x V2)/273

====> V2 = 41.9 ml

Hence, % if Nitrogen = (28 x 41.9 x 100)/22400

= 5.238

=6.25%(nearly)

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