Question no 52 fast..
Answers
Answer:
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Area of ABC=49root3
Thetha=60°(equilateral triangle)
Let each side of the triangle be 'a' cm
Area of equilateral triangle =(root3/4)x(side) ^2
=>49root3=root3/4xa^2
=>a^2=49root3x4/root3
=>a^2=49x4
=>a^2=196
=>a=14cm
Radius of the circle half the length of the side of triangle ABC(GIVEN)
Therefore radius (r) =14/2=>r=7cm
Area of sector =( theta/360)xpi r^2
Area of the sector = 60/360x22/7 x7^2
=1/6x22x7
=154/6cm^2
Required area = area of triangle ABC-3(area of sector of angle 60° in a circle of radius 7cm)
Required area= 49root3-3x154/6
=49root3-154/2
=49root3-77
=49(1.732)-77
=84.868-77
=7.868cm^2
Hence area of the triangle not. Included in the circle is 7.868cm^2
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Answer:
area of shaded part is approx. 7.8 cm²
refer to the above attachment for the solution
