Question No. 57
Species which is least likely to exist is
O [Be(OH)4]2-
O BeF6 4-
O AIF6 3-
O [Al(OH)4]-
Answers
Answer:
ᴛʜᴜɴᴅᴇʀsᴛᴏʀᴍs ᴅᴇᴠᴇʟᴏᴘ ɪɴ ʜᴏᴛ ᴀɴᴅ ʜᴜᴍɪᴅ ᴀʀᴇᴀs. ʜɪɢʜ ᴛᴇᴍᴘᴇʀᴀᴛᴜʀᴇ ɪɴ ᴛʜɪs ᴀʀᴇᴀs ᴄᴀᴜsᴇ ʜᴏᴛ ʜᴜᴍɪᴅ (ᴡɪᴛʜ ᴡᴀᴛᴇʀ ᴠᴀᴘᴏᴜʀs) ᴀɪʀ ᴛᴏ ʀɪsᴇ ᴜᴘ. sᴏ, sᴛʀᴏɴɢ ᴜᴘᴡᴀʀᴅ ʀɪsɪɴɢ ᴡɪɴᴅs ᴡɪᴛʜ ᴡᴀᴛᴇʀ ᴅʀᴏᴘʟᴇᴛs ᴀʀᴇ ɢᴇɴᴇʀᴀᴛᴇᴅ. ... ᴜᴘᴡᴀʀᴅ ᴍᴏᴠᴇᴍᴇɴᴛ ᴏғ ᴀɪʀ ᴀɴᴅ ᴅᴏᴡɴᴡᴀʀᴅ ᴍᴏᴠᴇᴍᴇɴᴛ ᴏғ ᴡᴀᴛᴇʀ ᴅʀᴏᴘs, ᴛᴏɢᴇᴛʜᴇʀ, ᴄᴀᴜsᴇ ʟɪɢʜᴛɴɪɴɢ ᴀɴᴅ sᴏᴜɴᴅ.
Answer: BeF₆⁴⁻ is least likely to exist.
Explanation: Be is a s-block element with atomic number 4. So beryllium has 4 electrons as well as 4 protons. It has a mass number 9 , so it's neutron number is 5. It is a steel-grey, strong, lightweight and brittle alkaline earth metal. It is a divalent element that occurs naturally only in combination with other elements to form minerals.
Because of it's low atomic number and very low absorption for X-rays, the oldest and still one of the most important applications of beryllium is in radiation windows for x-ray tubes.
Due to the absence of vacant d-orbital in Be, BeF₆³⁻ is not formed as it doesn't have enough orbitals to accommodate extra electrons.
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