question no. 6 and with that also verify it please ??
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diyanagpal16:
Sum - 6973
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Answers
Answered by
2
hey mate here is your answer
a=17, an=350, d=9
a+(n-1) d=an
17+(n-1) 9=350
(n-1) d=350-17
(n-1) 9=333
(n-1) =333/9
n-1=37
n=37+1
n=38
sn=n/2(a+an)
s38=38/2(17+350)
s38=19(367)
therefore,
s38=6973
hope it helped you
please mark me as a brainliest
a=17, an=350, d=9
a+(n-1) d=an
17+(n-1) 9=350
(n-1) d=350-17
(n-1) 9=333
(n-1) =333/9
n-1=37
n=37+1
n=38
sn=n/2(a+an)
s38=38/2(17+350)
s38=19(367)
therefore,
s38=6973
hope it helped you
please mark me as a brainliest
please mark me as a brainliest
thanks bro
Answered by
0
a=17, tn=350, d=9
Tn=a+(n-1)d
tn=17+(n-1)9
350 = 17 + 9n - 9
350= 8 + 9n
350 - 8 = 9n
342 = 9n
342/9 =n
38 = n
There are 38 terms
Sum of T38
Sn = n/2(2a+(n-1)d)
S38 = 19(2 * 17 + (38-1) 9)
= 19(34 + (37*9))
=19(34+33)
=19 * 64
=12,16
Pls mark me as brainlist
Tn=a+(n-1)d
tn=17+(n-1)9
350 = 17 + 9n - 9
350= 8 + 9n
350 - 8 = 9n
342 = 9n
342/9 =n
38 = n
There are 38 terms
Sum of T38
Sn = n/2(2a+(n-1)d)
S38 = 19(2 * 17 + (38-1) 9)
= 19(34 + (37*9))
=19(34+33)
=19 * 64
=12,16
Pls mark me as brainlist
what 37×9=33
it is wrong
yeah I saw it that I added only 33
it's 34+333
glad you understood your mistake
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