Chemistry, asked by piyushraj9475, 5 hours ago

Question No. 6 (last one)
Don't write anything useless , if u guys know it then pls answer it !​

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Answered by yasukoyoshidalov
0

Answers:

∴H2SO4 = 98.06

H2=1.00g/mol×2= 2.00g/mol

S=32.06g/mol

O4=16.00g/mol×4= 64.00g/mol

∴HNO3 =63.01g/mol

H=1.00g/mol

N=14.01g/mol

O3=16.00g/mol×3= 48.00g/mol

∴NaOH=39.99g/mol

Na=22.99g/mol

O=16.00g/mol

H=1.00g/mol

∴H2PO4= 96.97

H2=1.00g/mol×2= 2.00g/mol

P=30.97g/mol

O=16.00g/mol×4= 64.00g/mol

∴CaCO3=100.09g/mol

Ca=40.08g/mol

C=12.01g/mol

O3=16.00g/mol×3= 48.00g/mol

∴CaO=56.08g/mol

Ca=40.08g/mol

O=16.00g/mol

∴C6H12O6=180.06g/mol

C6=12.01g/mol×6= 72.06g/mol

H12=1.00g/mol×12= 12.00g/mol

O=16.00g/mol×6= 96.00g/mol

∴H2C2O4=90.02g/mol

H2=1.00g/mol×2.00g/mol

C2=12.01g/mol×2= 24.02g/mol

O4=16.00g/mol×4= 64.00g/mol

∴C12H22O11=342.12g/mol

C12=12.01g/mol×12= 144.12g/mol

H22=1.00g/mol×22= 22.00g/mol

O11=16.00g/mol×11= 176.00g/mol

∴2(H22N)CO=100.03g/mol

2(H22)=2×(1.00g/mol×22)= 44.00g/mol

2(N)=2×(14.01g/mol)=28.02g/mol

C=12.01g/mol

O=16.00g/mol

Explanation:

find the molar mass of each atom in the compound then add them up.

Answered by keerthibhavya2020
1

Answer:

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