Question

Question no.6 pls. Help

Answer 1

Answer:

Explanation:

now moment of f1 about

o=10 * 0.25=

2.5NM(Clockwise}

so total

(2.5+2.5)

= 5nm

clockwise= -5nm

moment of force about a point = force * perpendicular distance of point from the force

moment = fr(and the symbol)

moment of f1 about a=10*0=0

moment of f1 about b= 10*0.5= 5nm(anticlockwise)

(do the same for b)

take clockwise as -ve and anticlockwise as +ve

so moment about a = 5Nm

moment about b=-5Nm