Question

question no. 6 plz... its very urgent...i will mark you as brainliest....plz plz plz...

Answer 1

We know that R = V/I
Here, V = 8±0.5 and I = 4±0.2

Now,
∆R/R = ± (∆V/V + ∆I/I)
= ± ( 0.5/8 + 0.2/4)
= ± ( 0.9/8)
Therefore percentage error is- ∆R/R × 100%
= ± (0.9/8) × 100 %
= ± 11.25%

Again, R = V/I
R = 8/4 = 2

Therefore value of resistance with its percentage error is
R ± (∆R/R × 100%)
= ( 2 ± 11.25%) ohm.

Hope that my answer helps you. Thank you.