question no.6 plzzzzzz
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Here's your answer!!
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1)In ∆ ABE and ∆ACF ,
=>BE =CF (Given)
=> <AEB =<AFC ( each 90° )
=> <A = <A (Common)
By criteria (AAS),
=> ∆ABE is congruent to ∆ACF
2)Since,
∆ABE is congruent to ∆ACF
So, AB = AC (By c.p.c.t )
_____________________________
Hope it helps you!! :)
___________________________
1)In ∆ ABE and ∆ACF ,
=>BE =CF (Given)
=> <AEB =<AFC ( each 90° )
=> <A = <A (Common)
By criteria (AAS),
=> ∆ABE is congruent to ∆ACF
2)Since,
∆ABE is congruent to ∆ACF
So, AB = AC (By c.p.c.t )
_____________________________
Hope it helps you!! :)
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madfoodie:
thanks
abe pgle quse 6 ka chahiye tha 5 ka nhi
Sorry, i didn't saw
Ask it again i'll answer it :)
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