Question

Question no. 7 Answer

Answer 1

angle adc =116 by linear pair and by angle sum in triangle adc=x+angle c +116=180....

so x =64/2=32degree

Answer 2

angle ADB =64 (as the line ab=ad)

angle (ADB +adc) = 180

64+ angle adc=180

angle of adc= 180-64

= 116

therefore,

angle (adc+dac+acd)=180

116+X+X= 180 ( ad= cd thus same angle at base)

116+2x=180

2x=180-116

2x=64

X=32

angle dac = X= 32 degree