Question

question no. 7 chemistry class 11 iit jee

Answer 1

no. of molecules in 64 g of SO2= 6.02×10^2molecules
now no. of molecules in 16g of SO2=6.02×10^23 ×16÷64=6.02×10^23/4=1.5×10^23
So I think option third is correct.

Answer 2

SO2
Weight of S = 32 g
Weight of O = 16 g
Weight of 1 mole of SO2 = 32 + 2×16
= 32+32
= 64g
Weight of 1 mole of SO2 = 64g
16 g = 1/4 mole
1 mole = 6.022×10²³ molecules
1/4 moles = 6.022/4 × 10²³ molecules
= 1.5055×10²³ molecules
Ans. is (C) 1.5×10²³

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