Question No. 7 In the given figure DE||BE and PB and PC is the angle bisector of ZB and ZC respectively. What is the perimeter (in cm) of AADE if AB = 18 cm, BC = 30 cm and AC = 24cm ? A D Р E B. С
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Step-by-step explanation:
Let BD=x cm. Then, DC=(6-x) cm.
Since AD is the bisector of ∠A.
∴
AC
AB
=
DC
BC
⇒
14
10
=
6−x
x
⇒
7
5
=
6−x
x
⇒ 30−5x=7x
⇒ 12x=30
⇒ x=
2
5
=2.5cm
⇒ BD=2.5cm and
DC=(6−x)cm=(6−2.5)cm=3.5cm
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