Question

Question no.8 Class 10

Answer 1

(i)

Given sin A = 1

= > sinA = sin 90

= > A = 90    ------ (1)

(ii)

Given : tan(A - B) = √3

= > tan(A - B) = tan 60

= > (A - B) = 60

= > 90 - B = 60 [from (i)]

= > -B = 60 - 90

= > -B = -30

= > B = 30.

Therefore, the value of A = 90 and B = 30.

Hope this helps!

Answer 2

tan(A-B) = root 3
tan(A-B) = tan 60°
A-B = 60° ------(i)

SinA = 1
SinA = Sin 90°
A = 90°

by putting value of a from equation second in equation 1

90-B = 60°
-B = 60°-90°
- B = -30°
B = 30°
A = 90°


hope it helps
thanks..



hope it helps
thank you..