question no 8. did not getting answer
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See the attachment for Reference
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Rectangle A= DH x PE
= 15 x 6
90cm²
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Triangle B = x AG x (EF)
EF= HD-AF
EF 15-5=10cm
Therefore,
Area Of ∆ B= x 4 x (10)
20cm²
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Triangle C= x BH x (DC)
DC=15-9=6cm
therefore,
Area of ∆ C= x 8 x (6)
24cm²
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Rectangle D= AF x AG
= 5 x 4
20cm²
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Rectangle E = BC x BH
= 9 x 8
72 cm²
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Area of Figure = A + B + C + D +E
= 90 + 20 + 24 + 20 + 72
22cm²
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