Math, asked by AjayAju44, 1 year ago

Question no 8 help.i could'nt edit my other question so......

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Answered by ShuchiRecites

$\textbf{ \huge{ Hello Mate! }}$

Here we will use exterior angle property which states that sum of two opposite interior angle is equal to exterior angle.

I am using " < " sign to demonstrate angle.

Given : PT bisects angle P so < QPT = TPR

To prove: < PQR + < PRS = 2 < PTR

In triangle PQT

< PQT + < QPT = < PTR ____(1)

Similarily,

< PTR + < TPR = < PRS

< PTR = < PRS - < TPR or

< PRS - < TPR = < PTR ___(2)

On adding (1) and (2) we get

< PQT + < PRS + ( < QPT - < TPR ) = < PTR + < PTR

< PQT + < PRS = 2 < PTR

$\textbf{ Q.E.D }$

Have great future ahead!

AjayAju44: I didn't understand fully. can u pls put <1 ,<2,<3.....it would be great if u help me.sorry for disturbing u

ShuchiRecites: Sorry dear, pardon please?

ShuchiRecites: I mean what u mean to say?

AjayAju44: If u could put like < PQT as <1 and

ShuchiRecites: From where u r not getting

AjayAju44: Second and third line after Similarly,

AjayAju44: And on adding (1) and (2)

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