Question

Question No. 8
Two point charges of 1 C and -1 uc are placed at x = 0 and x = 2 cm respectively. The electric potential at x = 4 cm will be
9x105 v
2 x 103 v
o 2x10 v
O Zero​

Answer 1

i think it is 0

v1=kx -1/r r is the distance between the point and orgin here r=4

similarly v2=kX1/R

IF P IS THE POINT THEN V AT P =V1+V2=0

HOPE IT IS USEFUL TO U

Answer 2

The electric potential energy is -2 × 10³ V

Explanation:

We know that Electric Potential at a distance r due to charge q is given by

$V=k\frac{q}{r}$

Where k is Coulomb's constant $=9\times 10^9$ kgm³/s⁴A²

Therefore,

Electric Potential at x = 4 m due to charges at x = 0 and x = 2 m

$V=k\frac{1\times 10^{-6}}{4}+k\frac{(-1\times 10^{-6})}{2}$

$\implies V=k\times 10^{-6}(\frac{1}{4}-\frac{1}{2}$

$\implies V=-9\times 10^9\times 10^{-6}\times\frac{1}{4}$

$\implies V=-9\times 10^3\times\frac{1}{4}$

$\implies V=-2.2\times 10^3$ Volts

Hope this answer is helpful.

Know More:

Q: Two point charges of 10C each are kept at distance of 3 m in vacuum. Calculate their electrostatic potential energy.​

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