question no 9 confusion plzz solve
who give correct answer will get more thanks plzz answer
faltu answer will be reported
Attachments:
Answers
Answered by
1
Answer: Given Equation is x^2 + 1/x^2 = 18
= > x^2 + (1/x^2) = 2 + 16
= > x^2 + (1/x^2) - 2 = 16
We can write it as,
= > x^2 + (1/x^2) - 2 * x * (1/x) = 16
We know that a^2 + b^2 - 2ab = (a - b)^2
= > (x - 1/x)^2 = 16
x=4
Sorry about x+1/x
Answered by
7
Given Equation is x^2 + 1/x^2 = 18
= > x^2 + (1/x^2) = 2 + 16
= > x^2 + (1/x^2) - 2 = 16
We can write it as,
= > x^2 + (1/x^2) - 2 * x * (1/x) = 16
We know that a^2 + b^2 - 2ab = (a - b)^2
= > (x - 1/x)^2 = 16
x=4
= > x^2 + (1/x^2) = 2 + 16
= > x^2 + (1/x^2) - 2 = 16
We can write it as,
= > x^2 + (1/x^2) - 2 * x * (1/x) = 16
We know that a^2 + b^2 - 2ab = (a - b)^2
= > (x - 1/x)^2 = 16
x=4
Similar questions