Question

Question No.93
Two particles of masses Mand 2M are at a distance D apart. Under their mutual gravitational force they start moving towards each other. The
acceleration of their centre of mass when they are D/2 apart is​

Answer 1

$\sf\large{\underline{\underline{Answer :}}}$

$\sf{\implies{0}}$

$\sf\large{\underline{\underline{Explaination :}}}$

$\sf{F=(G \times 2m \times m)/(d \times d)}$

Acceleration of mass m = $\sf{G\times 2m/d\times d}$

Acceleration of mass 2m = $\sf{-G\times m/d\times d}$

So, acceleration of centre of mass ⇒

$\sf\small\small{(m×G×2m/d×d-m×G×2m/d×d)/(2m+m)}$

$\sf{\implies{0}}$