Question

Question No. 96
The temperature at which protons in
proton gas would have enough energy to
overcome Coulomb barrier of
4.14 x 10-14 J is (Boltzmann constant
1.38 x 10-23 K-1)
(A)
y 109​

Answer 1

Answer:

Temperature of the protons is given as

$T = 4.47 \times 10^4 K$

Explanation:

Total energy of the fundamental particles is given as

$U = \frac{3}{2}kT$

here we know that

$U = 4.14 \times 10^{-14} J$

now we have

$4.14 \times 10^{-14} = \frac{3}{2}(1.38 \times 10^{-23})T$

now we have

$T = 4.47 \times 10^4 K$

#LEarn

Topic : thermal energy

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