Question

Question No. 97 :

Solve the question, please.

Thank you! ☺

Answer 1

The function is f(x) = x²/(x-2)

We know that x² is always ≥0 for real values of x.

So it will always positive and sign will depend on (x-2).

Now,,,

When x>2 then f(x)≥0

When x<2 then f(x) ≤0

and undefined at x=2

So the solution set when x²/(x-2) >0

is x∈ (2,∞)

Answer 2

Plz refer to the attachment for the answer

Thanks