Question

question no19. a²+2ab+b²-9c²?factories ​

Answer 1

Applying the identities: a

2

−b

2

=(a+b)(a−b) and (a+b)

2

=a

2

+b

2

+2ab

Using the above identities, the equation a

2

+2ab+b

2

−9c

2

can be factorised as follows:

a

2

+2ab+b

2

−9c

2

=(a+b)

2

−9c

2

=(a+b)

2

−(3c)

2

=(a+b+3c)(a+b−3c)

Hence, a

2

+2ab+b

2

−9c

2

=(a+b+3c)(a+b−3c)

Answer 2

Step-by-step explanation:

a*2 +. 2ab + b2-9c?

a*2+2ab+b*2= (a+b)*2

then

( a+b)*2-9c2

(a+b)*2-(3c)*2

using formula

A*2-B*2 = (A+B) (A-B)

(a+b-3c) (a+b+3c)