Question no23 please solve
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135° is the answer.
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Please mark as brainliest if it would be helpful to you
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vishalkhurana1:
Mark as brainliest!!!
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A +B +C=180;A+C=180-B ;A+C=90_(1)
A/2 +C/2=90/2
A/2+ C/2=45_(2)
NOW IN ∆AOC
A/2 +C/2 +<AOC=180°(ANGLE SUM PROPERTY)
45+<AOC=180°(FROM 2)
THEREFORE,<AOC=180-45=135°
A/2 +C/2=90/2
A/2+ C/2=45_(2)
NOW IN ∆AOC
A/2 +C/2 +<AOC=180°(ANGLE SUM PROPERTY)
45+<AOC=180°(FROM 2)
THEREFORE,<AOC=180-45=135°
wow
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