question no42.. who will answer me first I'll make it as a brainlist answer...plzzzzz
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1 mol of water=18 g
10 mol of water =180 g
So you bring 180 g of water.
No. of molecules in 1g water=1/18 * 6.023*10^23
= 0.33 ×10^23.
no. of molecules in 180 g water=180*0.33*10^23
=59.4 * 10^23 molecules
10 mol of water =180 g
So you bring 180 g of water.
No. of molecules in 1g water=1/18 * 6.023*10^23
= 0.33 ×10^23.
no. of molecules in 180 g water=180*0.33*10^23
=59.4 * 10^23 molecules
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We will measure mass of water
Molar mass of water is 18
No.of moles=given mass/molar mass
Let given mass is X
10=X /18
X=18*10=180g
Second formula for finding moles
No.of moles=no.of particles/Avogadro's number
Let no.of molecules= Z
10=Z/6.022*10 raised to power 23
Z=6.022*10raised to power
kabhsai14:
I had left something I AM telling it here Z=6.022*10raised to power 23*10=6.022*10raised to power 24 now please mark it brainliest
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