Question

question no5 please , thanks

Answer 1

Answer:

In ∆ABC and ∆ADC

<BAC = <CAD ( Given )

AB = AD ( Given )

AC = CA ( Common )

•°• ∆ ABC ~= ∆ ADC (By SAS)

I Hope It Will Help!

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Answer 2

Answer:

In ∆ABC and ∆ADC

<BAC = <CAD ( Given )

AB = AD ( Given )

AC = CA (Common side )

•°• ∆ ABC ~= ∆ ADC (By SAS)

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