Question number 1? Note solve with explaination
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ad=ad(same side)ab=ac,bd=dc by dad test and =~=acd
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In equilateral triangle,
all sides are equal, so
In triangle ABD and triangle ACD
AD = AD (common)
BD = CD (ad is median so it cut BC in two equal part CD = BD)
AB = AC ( given )
By SSS congrence criteria
triangle ABD congrent to triangle ACD
Hence proved.
all sides are equal, so
In triangle ABD and triangle ACD
AD = AD (common)
BD = CD (ad is median so it cut BC in two equal part CD = BD)
AB = AC ( given )
By SSS congrence criteria
triangle ABD congrent to triangle ACD
Hence proved.
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