Question number 1 plz answer fast.
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<OCA + <OCB = <ACB
<ACB= 50
<ACB Is inscribed angle
< AOB Is central angle
according to inscribed angle theorem
<ACB =2 <AOB
<AOB= 1/2< ACB
= 1/2 × 50
=25
< AOB = 25
<ACB= 50
<ACB Is inscribed angle
< AOB Is central angle
according to inscribed angle theorem
<ACB =2 <AOB
<AOB= 1/2< ACB
= 1/2 × 50
=25
< AOB = 25
Davidbappa:
I don't think the answer is correct as by looking at the diagram we can judge that angle AOB is much greater than angle ACB but your answer do not seems to be like that.
you can check it on google
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