Question number 10 please
Answers
Answer:
(Use π=3.14 and 3=1.73)
Step-by-step explanation:
In the mentioned figure,
O is the centre of circle,
AB is a chord
AXB is a major arc,
OA=OB= radius = 15 cm
Arc AXB subtends an angle 60o at O.
Area of sector AOB=36060×π×r2
=36060×3.14×(15)2
=117.75cm2
Area of minor segment (Area of Shaded region) = Area of sector AOB− Area of △ AOB
By trigonometry,
AC=15sin30
OC=15cos30
And, AB=2AC
∴ AB=2×15sin30=15 cm
∴ OC=15cos30=1523=15×21.73=12.975 cm
∴ Area of △AOB=0.5×15×12.975=97.3125cm2
∴ Area of minor segment (Area of Shaded region) =117.75−97.3125=20.4375 cm2
Area of major segment = Area of circle − Area of minor segment
=(3.14×15 ×15)−20.4375
(3.14×15 ×15)−20.4375 =686.0625cm2
hope it helps:)