question number 11 and 12 please solve it
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hello friend...!
question 11 )
• W = i - 2j + 2k
• r = 4j - 3k.
we should calculate the magnitude of V
we know V = r x W
therefore, the cross product between the r and W gives V
r x W = 2i - 3j -4k = v
therefore the magnitude of V is √29
question 12)
the adjacent sides of a parallelogram are
V1 = i + 2j + 3k
V2 = 3i - 2j + K
we should calculate the area of the parallelogram
we know that, area of a parallelogram is
therefore,
V1 x V2 = 8√3.
_______________________________
hope it helps...!!
question 11 )
• W = i - 2j + 2k
• r = 4j - 3k.
we should calculate the magnitude of V
we know V = r x W
therefore, the cross product between the r and W gives V
r x W = 2i - 3j -4k = v
therefore the magnitude of V is √29
question 12)
the adjacent sides of a parallelogram are
V1 = i + 2j + 3k
V2 = 3i - 2j + K
we should calculate the area of the parallelogram
we know that, area of a parallelogram is
therefore,
V1 x V2 = 8√3.
_______________________________
hope it helps...!!
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