Question

question number 11 and 12 plsss

Answer 1

$x = 180 - 100 \\ = > x = 80 \\ y = 180 - (30 + 20) \\ = > y = 180 - 50 \\ = > y = 130 \\ \frac{(x + y)}{(y - x)} = \frac{80 + 50}{50 - 80} \\ \: \: \: \: \: \: \: \: \: \: \: = \frac{130}{ - 30 } \\ = \frac{13}{ - 3} \\ \\ this \: is \: the \: answer \: of \: 11$


12) Angle AOC = 180-80= 100°
=>x= Angle AOC ÷2
=> x= 100÷2=50°



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