Question number 12 fast it's urgent
Attachments:
Answers
Answered by
0
here is the answer
pls refer to image above.
pls refer to image above.
Attachments:
shreyamittal3132:
pls mark as brainliest
are you satisfied with the answer
Answered by
0
Answer:
Step-by-step explanation:
Sec^2A(Sec^2A-1)
Sec^2A*Tan^2A
(1+Tan^2A)Tan^2A
Tan^2A+Tan^4A
R.H.S proved
wrong answer
Sorry for the mistake
Similar questions