Math, asked by yukthisrinivas2004, 9 months ago

Question Number: 12
The number of digits in (49)53 [Given log 49 = 1.6902] is
(A) 89
(B) 90
N
(C) 91
(D) 92
DA
B
C​

Answers

Answered by anupsingh9345468
1

Answer:

91

Step-by-step explanation:

mark as brainlist answer

Answered by PoojaBurra
1

Given:

log₁₀(49) = 1.6902

To find:

The number of digits in (49)⁵³

Calculation:

The given number is (49)⁵³

Taking log for the number

=>  log₁₀(49)⁵³ = 53 × log₁₀(49)

By substituting [log₁₀(49) = 1.6902], we get

=>  53 × log₁₀(49) = 53 × 1.6902        

                             = 89.5806

                             ≈ 90

The number of digits in (49)⁵³ is 90

 

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