Question

question number 16 1st part i will mark u as brainliest​

Answer 1

Answer:

hope it will help u mark as brainliest

Answer 2

Step-by-step explanation:

LHS

(tan∅ + sec∅ - 1)/(tan∅ - sec∅ + 1)

=> (tan∅ + sec∅ - 1)/(-sec∅ + tan∅ + sec²∅ - tan²∅)

=> (tan∅ + sec∅ - 1)/[-(sec∅ - tan∅) + (sec∅ + tan∅)(sec∅ - tan∅)]

=> (tan∅ + sec∅ - 1)/[(sec∅ - tan∅)(-1 + sec∅ + tan∅)]

=> 1/sec∅ - tan∅

=> 1/(1/cos∅ - sin∅/cos∅)]

=> 1/(1 - sin∅)/cos∅)]

=> cos∅/1-sin∅

#Hope my answer will help you!