Question

Question number 19 please...

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

p(x)=x^4–2x^3+3x^2-ax+b

By remainder theorem, when p(x) is divided by (x-1) and (x+1) , the remainders are equal to p(1) and p(-1) respectively.

according to the given quest.

p(1)=5 and p(-1)=19

(1)^4–2(1)^3+3(1)^2-a(1)+b=5                 (-1)^4–2(-1)^3+3(-1)^2-a(-1)+b=19       =   1–2+3-a+b=5                                        =1-(-2)+3+a+b=19

=-a+b=5–1+2–3                                         = 1+2+3+a+b=19

 =-a+b=3                                                       =a+b=19–1–2–3=>13

Adding these two equations,we get

-a+b+a+b=3+13

=> 2b=16

=> 2b/2=16/2

=> b=8

Putting b=8 in a+b=13 , we get

a+8=13

=> a=13–8

=> a=5

Therefore, a=5 and b=8 .