Math, asked by gaurav337, 1 year ago

question number 2

no smapping

Attachments:

Answers

Answered by Anonymous
1
= x ^ 3 - 8 y ^ 3 + 27 z ^ 3 + 18xyz

= ( x )^3 + ( -2 y ) ^3 + ( 3z ) ^ 3 - 3 ( x ) ( -2y ) ( 3 z )

We know that,
 
A ^ 3 + B^ 3 + C ^ 3 - 3ABC = ( A + B + C ) ( A ^2 + B^2 + C^2 - AB - BC -CA)

= [ x + ( -2 y ) + 3z ] [ x^2 + ( -2y ) ^2 + ( 3z )^2 - x ( -2y) - ( -2y ) 3z - ( 3z)x]

= ( x - 2y + 3z ) ( x^2 + 4y^2 + 9z^2 +2xy +6yz- 3zx)

gaurav337: thank you
Anonymous: ur wlcm bro
Anonymous: Thanks
Answered by Anonymous
0

Step-by-step explanation:

In order to change what is on the outside, you must change what is on the inside.. In order to change what is on the outside, you must first change what is on the inside.

Similar questions