Question

question number 2 plz help me​

Answer 1

Answer:

$\huge\bf\pink{\mid{\overline{\underline{Your\:Solution}}}\mid}$

Step-by-step explanation:

$The\:Given\:Quadratic\:Equation\:is\:(a^{2} +9)x^{2} +13x+6a$

$Let\:the\:\:Zero\:of\:the\:Quadratic\:Polynomial\:be\:a$

$The\:Other\:Zero\:of\:the\:Quadratic\:polynomial\:is\:\frac{1}{a}$

$Product\:of\:the\:Zeroes\:=a\:X\:\frac{1}{a}=1$

$(Product\:of\:Zeroes=\frac{Constant\:term}{Coefficient\:of\:x^{2} } )$

$\frac{6a}{a^{2} +9}=1$

$6a=a^{2} +9$

$a^{2}-6a+9=0$

$(a-3)^{2}=0$

$a-3=0$

$a=3$

$Thus\:the\:Value\:a\:is\:3$

Answer 2

Step-by-step explanation:

refer to the attachment