Question number 20 part 3
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According to the graph ,
Initial velocity u = 0 m/s
Final velocity v = 40 m/s
Total time taken = 2 hrs. = 2×3600 sec
then,
By First laws of motion :
![v = u + at \\ \\ <br />40 = 0 + a×7200 \\ \\ <br />40 = a \times 7200 \\ \\ a = \frac{40}{7200} \\ \\ a = \frac{1}{180} \: m {s}^{ - 2} v = u + at \\ \\ <br />40 = 0 + a×7200 \\ \\ <br />40 = a \times 7200 \\ \\ a = \frac{40}{7200} \\ \\ a = \frac{1}{180} \: m {s}^{ - 2}](https://tex.z-dn.net/?f=v+%3D+u+%2B+at+%5C%5C+%5C%5C+%3Cbr+%2F%3E40+%3D+0+%2B+a%C3%977200+%5C%5C+%5C%5C+%3Cbr+%2F%3E40+%3D+a+%5Ctimes+7200+%5C%5C+%5C%5C+a+%3D+%5Cfrac%7B40%7D%7B7200%7D+%5C%5C+%5C%5C+a+%3D+%5Cfrac%7B1%7D%7B180%7D+%5C%3A+m+%7Bs%7D%5E%7B+-+2%7D+)
Now ,
By Third laws of motion :
![{v}^{2} = {u}^{2} + 2as \\ \\ {40}^{2} = {0}^{2} + 2 \times \frac{1}{180} \times s \\ \\ 1600 = \frac{1}{90} \times s \\ \\ s = 1600 \times 90 \: \: m \\ \\ s = 144000 \: \: m \\ \\ s = 144 \: \: km {v}^{2} = {u}^{2} + 2as \\ \\ {40}^{2} = {0}^{2} + 2 \times \frac{1}{180} \times s \\ \\ 1600 = \frac{1}{90} \times s \\ \\ s = 1600 \times 90 \: \: m \\ \\ s = 144000 \: \: m \\ \\ s = 144 \: \: km](https://tex.z-dn.net/?f=+%7Bv%7D%5E%7B2%7D+%3D+%7Bu%7D%5E%7B2%7D+%2B+2as+%5C%5C+%5C%5C+%7B40%7D%5E%7B2%7D+%3D+%7B0%7D%5E%7B2%7D+%2B+2+%5Ctimes+%5Cfrac%7B1%7D%7B180%7D+%5Ctimes+s+%5C%5C+%5C%5C+1600+%3D+%5Cfrac%7B1%7D%7B90%7D+%5Ctimes+s+%5C%5C+%5C%5C+s+%3D+1600+%5Ctimes+90+%5C%3A+%5C%3A+m+%5C%5C+%5C%5C+s+%3D+144000+%5C%3A+%5C%3A+m+%5C%5C+%5C%5C+s+%3D+144+%5C%3A+%5C%3A+km)
:. Total distance cover in 2 hrs. is 144 km
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《《 Hope it may helpful to you 》》
○○○○○○ @ajaman ○○○○○○○
●••••• ☆ Brainly Star ☆ •••••●
《《 Here is your answer 》》
________________________
According to the graph ,
Initial velocity u = 0 m/s
Final velocity v = 40 m/s
Total time taken = 2 hrs. = 2×3600 sec
then,
By First laws of motion :
Now ,
By Third laws of motion :
:. Total distance cover in 2 hrs. is 144 km
_____________________________
《《 Hope it may helpful to you 》》
○○○○○○ @ajaman ○○○○○○○
●••••• ☆ Brainly Star ☆ •••••●
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