Question

question number 3 and 2

Answer 1

Answer:

2) ₹300 ; 3) ₹15.75 or ₹15 75 p

Step-by-step explanation:

2) Formula → CP = $\frac{SP}{(1-\frac{Loss}{100})}$

Here, SP = ₹270 ; Loss = 10%

So, CP = $\frac{270}{1-\frac{10}{100}}$

⇒ CP = $\frac{270}{\frac{90}{100}}$

⇒ CP = $\frac{270}{90}$ × 100

⇒ CP = 3 × 100

⇒ CP of the article = ₹300

3) First find duration between August 10 and October 22.

The duration is 73 days = $\frac{73}{365}$ year

Formula → SI = $\frac{P*R*T}{100}$

Here, P = ₹900 ; R = $8\frac{3}{4}$% ; T = $\frac{73}{365}$ yrs

So, SI = $\frac{900*8\frac{3}{4}*\frac{73}{365}}{100}$

⇒ SI = $\frac{900*\frac{35}{4}*\frac{73}{365}}{100}$

⇒ SI = $\frac{900*35*73}{100*4*365}$

⇒ SI = $\frac{9*7*73}{4*73}$

⇒ SI = $\frac{9*7}{4}$

⇒ SI = $\frac{63}{4}$

⇒ SI = ₹15.75 or ₹15 75 p