Math, asked by pinkisharma1980anil, 9 months ago

question number 40
please tell fast
I will mark u as brainliest​

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Answers

Answered by TakenName
1

A diagonal is √2 times the side x.

x√2=40

x=20√2

Now its area is 20√2 × 20√2 = 800.

As two lines pass the center of the square, it will divide the area into four and equally.

So red, green takes 400 cm² equivalently.

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The area of the last triangle is ½×10×12.

Now the area for black is 60 cm².

Answered by singrohaankit023
0

Step-by-step explanation:

Diagonal= AC=BD=40

Area of right angle triangle= (Base*perpendicular)/2

Since its a square, Base=Perpendicular= 40/2= 20

Area of AOB= (20+20)/2= 200 centimetre square

Each colour in square will have 200 cm sq of area. So total 800 cm sq.

Now in bottom triangle,

Area of triangle= (Base*height)/2

To find hight, draw a perpendicular.

from this right angle triangle you get hight by using

 {a}^{2}  +  {b}^{2}  =  {c}^{2}

you get hight=12

then area of bottom triangle= (12*10)/2= 60cm sq.

Area of black= 60 cm sq.

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