Question Number : 41
The solubility of CO2 in water at 25 °C and 1 atm is 0.034 mol/L. The amount of CO2 present in 200 mL of this solution is
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(D) is correct option
according to solubility rules
(0.034 mol/1000ml)
=(X mol/200ml)
or, X = 0.034/5= 6.8×^10^-3
= 0.068 mol
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