Question

Question number 45,46,47 answer fast have to revise plz;:))

Answer 1

Ans 45: The LCM of two numbers is 180. The HCF of those two numbers is 6. One of those numbers is 30. Let another number be x. 
You have to solve and equation to find another number. 
LCM × HCF = Product of two numbers
180 × 6 = 30x
30x = 180 × 6
30x = 1080
x = 36
∴ Another number is 36. 
You can also check this. 

Ans 46: First, find the LCM of 520 and 468. 
LCM of 520 and 468 is 4680. 
4680 - 17 = 4663
∴ The required number is 4663. 

Sorry friend, I can answer only Q45 and Q46. I cannot solve Q47. 
Hope this may help you. 

Answer 2

Answer:

Ans 45: The LCM of two numbers is 180. The HCF of those two numbers is 6. One of those numbers is 30. Let another number be x. 

You have to solve and equation to find another number. 

LCM × HCF = Product of two numbers

180 × 6 = 30x

30x = 180 × 6

30x = 1080

x = 36

∴ Another number is 36. 

You can also check this. 

Ans 46: First, find the LCM of 520 and 468. 

LCM of 520 and 468 is 4680. 

4680 - 17 = 4663

∴ The required number is 4663. 

Sorry friend, I can answer only Q45 and Q46. I cannot solve Q47. 

Step-by-step explanation:

Hope this answer will help you m