Question

question number 5 answe r fast first corrext answer brainliest

Answer 1

$Given : 8^{x - 2} * (\frac{1}{2})^{4 - 3x} = (0.0625)^x$

$= > (2^3)^{x - 2} * (2^{-1})^{(4 - 3x)} = (\frac{1}{16})^x$

$= > 2^{3(x - 2) - 1(4 - 3x)} = (2^{-4})^x$

$= > 2^{3(x - 2) - 1(4 - 3x)} = 2^{-4x}$

$= > 3(x - 2) - 1(4 - 3x) = -4x$

$= > 3(x - 2) - (4 - 3x) = -4x$

$= > 3x - 6 - 4 + 3x = -4x$

$= > 6x - 10 = -4x$

$= > 10x = 10$

$= > x = 1.$

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$= > \boxed{Answer : 1} - Option (D)$

Hope this helps!