Question

question number 7th and 8th

Answer 1

7. let x be the no.
acc. to question
$- (3) { }^{ - 1} \times x = (7) {}^{ - 1}$
$x = \frac{1}{7} \times 3$

$x = \frac{3}{7}$Therefore the no. is
$\frac{3}{7}$
8.
$\frac{a}{b} = ( \frac{3}{4} ) {}^{2} \times ( \frac{3}{4} ) {}^{0}$
$\frac{a}{b} = ( { \frac{3}{4} })^{2}$
Now,
$( \frac{a}{b} ) {}^{3} = ( \frac{3}{4} ) {}^{6}$
$( \frac{a}{b} ) {}^{3} = ( \frac{729}{4096} )$