Question

QUESTION NUMBER 8...CAN SOME PLS ANSWER THIS QUESTION QUICKLY...PLSSSSSS...

Answer 1

Step-by-step explanation:

$according \: to \: question \: the \: no. \: are \\ conjugate \: of \: each \: other \\ therefore \\ - 3 + i {x}^{2} y = {x}^{2} + y - 4i \\ comparing \: real \: part \: and \: imaginary \: \\ part \\ {x }^{2} + y = - 3........(1) \\ {x}^{2} y = - 4 = > {x}^{2} = \frac{ - 4}{y} ....(2) \\ put \: in \: (1) \\ \frac{ - 4}{y} + y = - 3 \\ = > - 4 + {y}^{2} = - 3y \\ = > {y}^{2} + 3y - 4 = 0 \\ = > {y}^{2} + 4y - y - 4 = 0 \\ = > y(y + 4) - 1(y + 4) = 0 \\ = > (y + 4)(y - 1) = 0 \\ \\ y = 1 \: or \: y = - 4 \\ if \: y = 1 \: then \: {x}^{2} = \frac{ - 4}{1} = > x = \sqrt{ - 4} = 2i \\ if \: y = - 4 \: then \: {x}^{2} = \frac{ - 4}{ - 4} = 1 = > x = 1$