Question

question number 8 help me

Answer 1

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Answer 2

$\large \tt AHOY!! \:$

given :-

angle BOD = 150°

therefore angle DAB = 150/2 (since angle subtended on the circle is half of the angle subtended in the center by the same arc)

= 75°

here, DABP is a cyclic quadrilateral since all the vertex of the quadrilateral is lying on the same circle and we know that the sum of opposite angles in a cyclic quadrilateral is 180°

therefore angle DAB + angle BPD = 180°

=> 75° + angle BPD = 180°

=> angle BPD = 180° - 75°

=> angle BPD = 105°

$\large \tt HOPE \: THIS \: HELPS!!$