Math, asked by shivam97643678, 1 year ago

question number 9 solve it please

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Answered by nikky28
0
unit digit of 1^33=1
unit digit of 2^33=unit digit((2^4)^8.2)=unit digit(6×2)=2.
unit digit of 3^33=unit digit((3^4)^8.3)=unit digit(1×3)=3.
unit digit of 4^33=unit digit((4^4)^8.4)=unit digit(6×4)=4.
unit digit of 5^33=unit digit((5^4)^8.5)=unit digit(5×5)=5.
unit digit of 6^33=unit digit((6^4)^8.6)=unit digit(6×6)=6.
unit digit of 7^33=unit digit((7^4)^8.7)=unit digit(1×7)=7.
unit digit of 8^33=unit digit((8^4)^8.8)=unit digit(6×8)=8.
unit digit of 9^33=unit digit((9^4)^8.9)=unit digit(1×9)=9.
unit digit of 10^33=unit digit((10^4)^8.2)=unit digit(0×10)=0.

so, unit digit of 1^33+2^33+3^33+4^33 ....... 89^33=unit digit (9(1+2+3+4+5+6+7+8+9))=unit digit (9×45)=5 ANS...


shivam97643678: can you explain the process you have used to solve my question
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